X^2+8x=308

Solution for X^2+8x=308 equation:

X^2+8X=308

We move all terms to the left:

X^2+8X-(308)=0

a = 1; b = 8; c = -308;
Δ = b2-4ac
Δ = 82-4·1·(-308)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-36}{2*1}=\frac{-44}{2}
=-22
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+36}{2*1}=\frac{28}{2}
=14
$